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### Question Asked by a Student from EXXAMM.com Team

Q 1135223162.     If (2,3,5) is one end of a diameter of the sphere x^2+y^2+z^2-6x-12y-2z+20=0 , then the coordinates of the other end of the diameter is :
JEE 2007
A

(4,9,-3)

B

 (4,-3,3)

C

 (4,3,5)

D

(4,3,-3)

#### HINT

Comparing by the standard equation of a sphere, we get the centre as given point. so one end of the diameter is given we can easily calculate the other end of the diameter.

(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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