### Question Asked by a Student from EXXAMM.com Team

Q 1227434381.     The value of k such that (x−4)/1=(y−2)/1=(z−k)/2 lies in the plane 2x – 4 y + z = 7 , is
JEE 2003 Prelims
A

4

B

7

C

-7

D

-4

#### HINT

Let t be any parameter; Equation of straight line (x−4)/1 = (y−2)/1=(z−k)/2= t then any point on this line can be written as, x = 4+t, y = 2+t , z = 2t+k

(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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