Q .     An ellipse of eccentricity `(2sqrt2)/3` is inscribed in a circle.

A point is chosen randomly within the circle. The probability that the point lies outside the ellipse is

JEE 2002
A

`2/3`

B

`4/9 `

C

`1/9`

D

`1/3`

HINT

If `′e′` is the eccentricity then Area of ellipse `= πab=πaasqrt(1−e^2)`,
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