Q 1134512452.     A magnetic needle lying parallel to a magnetic field is turned through `60^0`. The work doen on it is `w`. The torque required to maintain the magnetic needle in the position mentioned above is

A

`sqrt3w`

B

`sqrt3/2w`

C

`w/2`

D

`2w`

HINT

Work done is equal to change in potential energy of needle.
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