Q 1173556446.     `veca!=vec0,vecb!=vec0,vecc!=vec0,`

`veca xxvecb=vec0,vecb xx vecc=vec0`

Then `veca x vecc=`

EAMCET 2013
A

`vecb`

B

`veca`

C

`vec0`

D

`veci+vecj+veck`

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