Q 1585823767.     The relation between efficiency `\eta` of a heat engine and the co-efficient of performance `\alpha` of a refrigerator is:

EAMCET 2015
A

`\eta=\ frac{1}{1-\alpha}`

B

`\eta=\ frac{1}{1+\alpha}`

C

`\eta=1+\alpha`

D

`\eta=1-\alpha`

HINT

`\Rightarrow \eta=1-\ frac{T_2}{T_1}` `alpha=frac{T_2}{T_1-T_2}`

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