Q 1610345210.     There is a plane of uniform positive charge
density `sigma` parallel to the `yz`-plane and located
at `x = 2d`. A point charge `+ q` is placed at the
origin. Solve for the position `x` along the
`x`-axis, where a positive test charge will have
a net force of zero.

GGSIPU 2015
A

`x = (2pi sigma)/d`

B

`x = sqrt (q /(2 pi xi rho))`

C

`x =sqrt (2 pi sigma /d)`

D

`x =-2d`

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