Q 2371191926.     Given `0 < x < pi/4, pi/4 < y < pi/2`,

`a= sum_(k=1)^(oo) (-1)^k tan^(2k) x` and

`b= sum_(k=1)^(oo) (-1)^k cot^(2k) y`, then

`sum_(k=0)^(oo) tan^(2k) x cot^(2k) y ` is equal to

BITSAT Mock
A

`a + b - ab`

B

` (ab)/(a+b -1)`

C

`1/a +1/b -1/(ab)`

D

`1/a+1/b +1/(ab)`

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