Q 2489001817.     A man measures the period of simple pendulum inside a stationary lift and finds it to be `T` second. If the lift accelerates downwards with acceleration of `g/4` the period of oscillation will be

BCECE 2011 Stage 1
A

`T xx sqrt 3/2 s`

B

`T xx 2/sqrt 3 s`

C

`T/2 s`

D

`sqrt T s`

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