Distance between the two planes: `2x + 3y + 4z=4` and `4x + 6y + 8z= 12` is
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Q 2667267185.
Distance between the two planes: `2x + 3y + 4z=4`
and `4x + 6y + 8z= 12` is
A
`2` units
B
`4` units
C
`8` units
D
`2/(sqrt (29) )` units
HINT
Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)
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