(a) The conductivity of 0.001 mol `L^-1` solution of `CH_3COOH` is `3.905 × 10^-5` S `cm^-1`. Calculate its molar condu

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Q 2646867773.     (a) The conductivity of 0.001 mol `L^-1` solution of `CH_3COOH` is `3.905 × 10^-5` S `cm^-1`. Calculate its molar conductivity and degree of dissociation (`α`)

Given `λ°(H^+ )= 349.6 S cm^2 mo^l-1` and `λ°(CH_3COO^- )= 40.9 S cm^2mol^-1`.

(b) Define electrochemical cell. What happens if external potential applied becomes greater than `E_(cell)^°` of electrochemical cell?
CBSE-12th 2016

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