A sample of `AgCl` was treated with `5.00` mL of `1.5` M `Na_2CO_3` solution to give `Ag _2CO_3`. The remaining solution

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Q 2636723672.     A sample of `AgCl` was treated with `5.00` mL of `1.5` M `Na_2CO_3` solution to give `Ag _2CO_3`. The remaining solution contained `0.0026` g of `Cl^(-)` ions per litre. Calculate the solubility product of `AgCl. [K_(sp) (Ag_ 2CO_3 ) = 8.2 xx 10^(-12)]`
JEE 1997
A

`6 xx 10^(-8)`

B

`4 xx 10^(-8)`

C

`9 xx 10^(-8)`

D

`2 xx 10^(-8)`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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