A solution is prepared by mixing `8.5 g` of `CH_2 Cl_2` and `11.95 g` of `CHCl_3`. If vapour pressure of `CH_2Cl_2` and

Ask a Question


Question Asked by a Student from EXXAMM.com Team


Q 2741123923.     A solution is prepared by mixing `8.5 g` of `CH_2 Cl_2` and `11.95 g` of `CHCl_3`. If vapour pressure of `CH_2Cl_2` and `CHCl_3` at `298 K` are `415` and `200 mmHg` respectively, the mole fraction of `CH Cl_3` in vapour form is : (Molar mass of `Cl =35.5 g mol^(-1)`)
JEE 2017 Mains 9 April
A

`0.675`

B

`0.325`

C

`0.162`

D

`0.486`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

Find instant solution to any question from our database of 1.5 Lakh + Questions

 


Access free resources including

  • 100% free video lectures with detailed notes and examples
  • Previous Year Papers
  • Mock Tests
  • Practices question categorized in topics and 4 levels with detailed solutions
  • Syllabus & Pattern Analysis

Engineering


Medical


Banking


DEFENCE


SSC


RRB


CBSE-NCERT


OLYMPIAD