An excess of liquid mercury is added to an acidified solution of `1 .0 xx 10^(-3) M Fe^(3+)`. It is found that `5%` of `

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Q 2637312282.     An excess of liquid mercury is added to an acidified solution of `1 .0 xx 10^(-3) M Fe^(3+)`. It is found that `5%` of `Fe^(3+)` remains at equilibrium at `25° C`. Calculate `E^0 (Hg^(2+) // Hg)` assuming that the only reaction that occurs is
`2Hg + 2Fe^(3+) -> Hg_2^(2+) + 2Fe^(2+)`
Given, `E^0 (Fe^(3-) // Fe^(2+) ) = 0.77 V`
JEE 1995

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(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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