An excess of liquid mercury is added to an acidified solution of 1 .0 xx 10^(-3) M Fe^(3+). It is found that 5% of 

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Q 2637312282.     An excess of liquid mercury is added to an acidified solution of 1 .0 xx 10^(-3) M Fe^(3+). It is found that 5% of Fe^(3+) remains at equilibrium at 25° C. Calculate E^0 (Hg^(2+) // Hg) assuming that the only reaction that occurs is
2Hg + 2Fe^(3+) -> Hg_2^(2+) + 2Fe^(2+)
Given, E^0 (Fe^(3-) // Fe^(2+) ) = 0.77 V`
JEE 1995

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