If the angle between the line `2(x+1)=y=z+4` and the plane `2x-y+\sqrt {\lambda}z+4=0` is `frac {\pi}{6}`, then the valu

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Q 1711434320.     If the angle between the line `2(x+1)=y=z+4` and the plane `2x-y+\sqrt {\lambda}z+4=0` is `frac {\pi}{6}`, then the value of `\lambda` is :
JEE 2014 Mains Paper 4
A

`frac {135}{7}`

B

`frac {45}{11}`

C

`frac {45}{7}`

D

`frac {135}{11}`

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Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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