If n is a natural number and n= p_1^(x_1) p_2^(x_2)p_3^(x_3) , where p_1, p_2 , p_3 are distinct prime factors, t

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Q 1649701613.     If n is a natural number and n= p_1^(x_1) p_2^(x_2)p_3^(x_3) , where
p_1, p_2 , p_3 are distinct prime factors, then the
number of prime factors for n is
CDS 2015 Paper-1
A

x_1+x_2+x_3

B

x_1x_2x_3

C

(x_1 +1)(x_2 +1)(x_3 + 1)

D

None of these

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