The distance of the point `(1, 0, 2)` from the point of intersection of the line `\ frac {x-2}{3}=\ frac {y+1}{4}=\ frac

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Q 1673523446.     The distance of the point `(1, 0, 2)` from the point of intersection of the line `\ frac {x-2}{3}=\ frac {y+1}{4}=\ frac {z-2}{12}` and the plane `x-y+z=16`, is
JEE 2015 Mains 4 April
A

`2\sqrt {14}`

B

`8`

C

`3\sqrt {21}`

D

`13`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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