 A is two years older than B who is twice as old as C. If Let the present ages of son and father be x and (60 -x) years r

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Q 1483634547.     A is two years older than B who is twice as old as C. If Let the present ages of son and father be x and (60 -x) years respectively. Then, (60 - x) - 6 = 5(x - 6) 54 - x = 5x - 30 6x = 84 x = 14. Son's age after 6 years = (x+ 6) = 20 years..Let the present ages of son and father be x and (60 -x) years respectively. Then, (60 - x) - 6 = 5(x - 6) 54 - x = 5x - 30 6x = 84 x = 14. Son's age after 6 years = (x+ 6) = 20 years..the total of the ages of A, B and C be 27, the how old is B? A 7

B 8

C 9

D 10

E 11

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