If P is the point (2, 1, 6), and another point Q is such that PQ is perpendicular to the plane x + y – 2z = 3

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Q 1207334288.     If P is the point (2, 1, 6), and another point Q is such that PQ is perpendicular to the plane x + y – 2z = 3 and the mid-point of PQ lies on it. Then the point Q is
A

(6, 5, + 2)

B

(6, 6, - 2)

C

(6, 11, – 2)

D

(6, 5, – 2)`

#### HINT

(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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