The value of `k` such that `(x−4)/1=(y−2)/1=(z−k)/2` lies in the plane `2x – 4 y + z = 7` , is

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Q 1227434381.     The value of `k` such that `(x−4)/1=(y−2)/1=(z−k)/2` lies in the plane `2x – 4 y + z = 7` , is
JEE 2003 Prelims
A

`4`

B

`7`

C

`-7`

D

`-4`

HINT

Let `t` be any parameter; Equation of straight line `(x−4)/1 = (y−2)/1=(z−k)/2= t` then any point on this line can be written as, `x = 4+t`, `y = 2+t` , `z = 2t+k`

Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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