If `(2,3,5)` is one end of a diameter of the sphere `x^2+y^2+z^2-6x-12y-2z+20=0` , then the coordinates of the other end

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Q 1135223162.     If `(2,3,5)` is one end of a diameter of the sphere `x^2+y^2+z^2-6x-12y-2z+20=0` , then the coordinates of the other end of the diameter is :
JEE 2007
A

`(4,9,-3)`

B

` (4,-3,3)`

C

` (4,3,5)`

D

`(4,3,-3)`

HINT

Comparing by the standard equation of a sphere, we get the centre as given point. so one end of the diameter is given we can easily calculate the other end of the diameter.

Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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