Perpendiculars are drawn from points on the line `(x+2)/2 =(y+1)/(-1)=z/3` to the plane `x + y + z = 3`. The feet of per

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Q 1114456359.     Perpendiculars are drawn from points on the line `(x+2)/2 =(y+1)/(-1)=z/3` to the plane `x + y + z = 3`. The feet of perpendiculars lie on the line
JEE 2012 Mains
A

`x/5=(y-1)/8=(z-2)/(-13)`

B

`x/2=(y-2)/3=(z-2)/(-5)`

C

`x/4=(y-1)/4=(z-2)/(-7)`

D

`x/2=(y-1)/(-7)=(z-2)/5`

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Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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