`2NOBr_(g) ⇌ 2NO_(g) + Br_(2(g))`. If `NOBr` is dissociated to the extent of `20%` at `T` K and a total pressure of `1

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Q 1158712604.     `2NOBr_(g) ⇌ 2NO_(g) + Br_(2(g))`. If `NOBr` is dissociated to the extent of `20%` at `T` K and a total pressure of `1.1` atm, then `K_p` for the formation of `NOBr` is
A

`1/(120)`

B

`160`

C

`1/(160)`

D

`120`

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Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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