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Q 1118112909.     1 mol `N_2` and 3 mol `H_2` are placed in a closed container at a pressure of 4 atm. The pressure falls to 3 atm at the same temperature
when the following equilibrium is attained.
`N_(2(g)) + 3 H_(2(g)) ⇌ 2NH_(3(g))`. The equilibrium constant `K_P` for dissociation of `NH_3` is:
Use formula: `n_2/n_1=P_2/P_1`
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)