1 mol N_2 and 3 mol H_2 are placed in a closed container at a pressure of 4 atm. The pressure falls to 3 atm at the

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Q 1118112909.     1 mol N_2 and 3 mol H_2 are placed in a closed container at a pressure of 4 atm. The pressure falls to 3 atm at the same temperature

when the following equilibrium is attained.

N_(2(g)) + 3 H_(2(g)) ⇌ 2NH_(3(g)). The equilibrium constant K_P for dissociation of NH_3 is:
A

1/0.5 × (1.5)^3 atm^-2

B

(0.5×(1.5)^3)/(3×3) atm^2

C

(3×3)/(0.5×(1.5)^3) atm^-2

D

0.5 × (1.5)^3 atm^2

#### HINT

Use formula: n_2/n_1=P_2/P_1

(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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