A 0.01 m solution of Pt(NH_3)_4Cl_4 in water had the freezing point of -0.056°C. Assuming 100% ionization of

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Q 1280191017.     A 0.01 m solution of Pt(NH_3)_4Cl_4 in water had the freezing point of -0.056°C. Assuming 100% ionization of the complex in solution, find the formula of the complex ion; given K_f (water) = 1.86 K kg mol e^(-1).
A

[Pt(NH_3)_4Cl_2]^(2+)

B

[Pt(NH_3)_2Cl_2]^(2+)

C

[Pt(NH_3)_4Cl_2]^(4+)

D

[Pt(NH_3)_2Cl_2]

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