A sample of `AgCl` was treated with 5.00 mL of `1.5 M Na_2CO_3` solution to give `Ag_2CO_3`. The remaining solution cont

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Q 1129212111.     A sample of `AgCl` was treated with 5.00 mL of `1.5 M Na_2CO_3` solution to give `Ag_2CO_3`. The remaining solution contained `0.0026 g` of `Cl^-` ions per litre. Calculate the solubility product of `AgCl. `
`[K_(sp) (Ag_2CO_3) = 8.2 × 10^(-12)]`
JEE 1997
A

`3.1 × 10^-8`

B

`2.0 × 10^-8`

C

`1.5 × 10^-8`

D

`4.2 × 10^-8`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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