At certain temperature only 50% of HI is dissociated into `H_2` and `I_2` at equlibrium . The equlibrium constant is :

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Q 1166512475.     At certain temperature only 50% of HI is dissociated into `H_2` and `I_2` at equlibrium . The equlibrium constant is :
A

`1.0`

B

`3.0`

C

`0.5`

D

`0.25`

HINT

Use : `{(2HI, ->, H_2 , + I_2),(a,,0,0),(a-a/2,,a/4,a/4):}` And `K = ([H_2][I_2])/[HI]^2`

Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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