Calculate emf of the following cell at 25 °C : `Fe|Fe^(2+)(0.001 M)| H^+(0.01 M)| H_2(g) (1 bar) | Pt (s)` `E°(F

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Q 1115278160.     Calculate emf of the following cell at 25 °C :

`Fe|Fe^(2+)(0.001 M)| H^+(0.01 M)| H_2(g) (1 bar) | Pt (s)`

`E°(Fe^(2+) | Fe)=-0.44 V E°(H^+ | H_2)=0.00 V`
A

`0.41` V

B

`0.44` V

C

`0.50` V

D

`0.30` V

HINT

Use formula: For, Ox + n e− → Red `E=E^{0}-frac{0.05916}{n}log _{10}frac {a_{{\text{Ox}}}}{a_{{\text{Red}}}}`

Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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