Equation of the plane that passes through the point (2,- 3, 1) and is perpendicular to the line joining the points (3,
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Q 2846712673.
Equation of the plane that passes through the point
(2,- 3, 1) and is perpendicular to the line joining the
points (3, 4,-1) and (2,-1, 5) is given by
A
x+5y -6z+19=0
B
x-5y+6z-23 =0
C
x + 5y- 6z = 19
D
None of these
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Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)
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