Equation of the plane that passes through the point (2,- 3, 1) and is perpendicular to the line joining the points (3,

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Q 2846712673.     Equation of the plane that passes through the point
(2,- 3, 1) and is perpendicular to the line joining the
points (3, 4,-1) and (2,-1, 5) is given by
A

x+5y -6z+19=0

B

x-5y+6z-23 =0

C

x + 5y- 6z = 19

D

None of these

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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