The standard state Gibbs free energies of formation of C(graphite) and C(diamond) at T = 298K are Delta_fG°  [C(gr

### Question Asked by a Student from EXXAMM.com Team

Q 2958312204.     The standard state Gibbs free energies of formation of C(graphite) and C(diamond) at T = 298K are

Delta_fG°  [C(graphite)] = 0 kJ mol^-1

Delta_f G° [C(diamond)] = 2.9 kJ mol^-1

The standard state means that the pressure should be 1 bar, and substance should be pure at a given temperature.
The conversion of graphite [C(graphite)] to diamond [C(diamond)] reduces its volume by 2 xx 10^-6 m^3 mol^-1. If C(graphite) is converted to C(diamond) isothermally at T = 298 K, the pressure at which C(graphite) is in equilibrium with C(diamond), is

[Useful information : 1 J = 1 kg m^2s^-2; 1 Pa = 1 kg m^-1 s^-2; 1 bar = 10^5 Pa]

A

14501 bar

B

29001 bar

C

1450 bar

D

58001 bar

#### HINT

(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

#### Access free resources including

• 100% free video lectures with detailed notes and examples
• Previous Year Papers
• Mock Tests
• Practices question categorized in topics and 4 levels with detailed solutions
• Syllabus & Pattern Analysis