5x + 2y = 2k and 2(k+ 1)x + ky = (3k+ 4)

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Q 2979567416.     Find the value of k for which the given system of equations has infinite number of solutions.
5x + 2y = 2k and 2(k+ 1)x + ky = (3k+ 4)
A

4

B

7

C

3

D

6

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Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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