A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that `AB (= a)`

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Q 3000091818.     A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that `AB (= a)` subtends an angle of `60^{\circ} ` at the foot of the tower, and the angle of elevation of the top of the tower from A or B is `30^{\circ}`. The height of the tower is
A

`\frac{2a}{\sqrt{3}}`

B

`2\sqrt{3}a`

C

`\frac{a}{\sqrt{3}}`

D

`a\sqrt{3}`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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