ABCD is a rectangle with A(-1, 2), B ( 3, 7 ) and AB : BC= 4 : 3. If P is the centre of the rectangle then the distance
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Q 3021123021.
ABCD is a rectangle with A(-1, 2), B ( 3, 7 ) and AB : BC= 4 : 3. If P is the centre of the rectangle then the distance of P from each corner is equal to
A
`frac{\sqrt{41}}2`
B
`frac{3\sqrt{41}}4`
C
`frac{2\sqrt{41}}3`
D
`frac{5\sqrt{41}}8`
HINT
Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)
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