ABCD is a rectangle with A(-1, 2), B ( 3, 7 ) and AB : BC= 4 : 3. If P is the centre of the rectangle then the distance

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Q 3080367217.     ABCD is a rectangle with A(-1, 2), B ( 3, 7 ) and AB : BC= 4 : 3. If P is the centre of the rectangle then the distance of P from each corner is equal to
A

`frac{\sqrt{41}}2`

B

`frac{3\sqrt{41}}4`

C

`frac{2\sqrt{41}}3`

D

`frac{5\sqrt{41}}8`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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