An observer finds that the angular elevation of a tower is `\theta`. On advancing a metres towards the tower, the elevat

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Q 3010891710.     An observer finds that the angular elevation of a tower is `\theta`. On advancing a metres towards the tower, the elevation is `45^{0}` and on advancing b metres nearer the elevation is `90^{0}-\theta`, then the height of the tower (in metres) is
A

`\frac{ab}{a+b}`

B

`\frac{ab}{a-b}`

C

`\frac{2ab}{a+b}`

D

` \frac{2ab}{a-b}`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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