An observer finds that the angular elevation of a tower is \theta. On advancing a metres towards the tower, the elevat

### Question Asked by a Student from EXXAMM.com Team

Q 3010891710.     An observer finds that the angular elevation of a tower is \theta. On advancing a metres towards the tower, the elevation is 45^{0} and on advancing b metres nearer the elevation is 90^{0}-\theta, then the height of the tower (in metres) is
A

\frac{ab}{a+b}

B

\frac{ab}{a-b}

C

\frac{2ab}{a+b}

D

 \frac{2ab}{a-b}

#### HINT

(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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