Let `A(1, 1, 1 ), B(2, 3, 5), C(-1, 0, 2)` be three points, then equation of a plane parallel to the plane `ABC` is at a
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Q 2651578424.
Let `A(1, 1, 1 ), B(2, 3, 5), C(-1, 0, 2)` be three points, then equation of a plane parallel to the plane `ABC` is at a distance `2` is
A
`2x-3y + z+ 2 sqrt 14 =0`
B
`2x- 3y + z sqrt 14 = 0`
C
`2x - 3y + z + 2 = 0`
D
`2x- 3y + z- 2 = 0`
HINT
Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)
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