(Use log 1.8 = 0.26, k_a of formic acid = 1.8 xx 10^-4, k_a of acetic acid =1.8 xx 10^-5, k_b, of ammonia = 1

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Q 2653423344.     (Use log 1.8 = 0.26, k_a of formic acid = 1.8 xx 10^-4, k_a of acetic acid =1.8 xx 10^-5, k_b, of ammonia = 1.8 xx 10^-5, k_(a_1) of H_2S = 10^-7 and k_(a_2) of H_2S = 10^-14, for the following matching ) Match the entries of column II for which the equality or inequality given in the the column I are satisfied
Column IColumn II
(A) 10^-5 M HCI solution > 0.1 M H_2S solution (p) α_(water) (degree of dissociation of water)
(B) CH_3COOH solution at pH equal to 4.74 = NH_4OH solution at pH equal to 9.26 (q) [OH^-]
(C) 0.1 M CH_3COOH solution= 1.0 M HCOOH solution (r) α (degree of dissociation of weak electrolytes)
(D) 0.1 M of a weak acid HA_1(ka = 10^-5 ) solution < 0.01 M of a weak acid HA_2(k_a = 10^-6) solution(S) pH
C

(A- p, q, r, s) ; (8- p, r) ; (C- r) ; (D- p, q, s)

#### HINT

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