(Use log 1.8 = 0.26, `k_a` of formic acid `= 1.8 xx 10^-4`, `k_a` of acetic acid `=1.8 xx 10^-5`, `k_b`, of ammonia `= 1

Ask a Question


Question Asked by a Student from EXXAMM.com Team


Q 2653423344.     (Use log 1.8 = 0.26, `k_a` of formic acid `= 1.8 xx 10^-4`, `k_a` of acetic acid `=1.8 xx 10^-5`, `k_b`, of ammonia `= 1.8 xx 10^-5`, `k_(a_1)` of `H_2S = 10^-7` and `k_(a_2)` of `H_2S = 10^-14`, for the following matching ) Match the entries of column II for which the equality or inequality given in the the column I are satisfied
Column IColumn II
(A) `10^-5` M HCI solution > `0.1 M H_2S` solution (p) `α_(water) (degree of dissociation of water)
(B) `CH_3COOH` solution at pH equal to 4.74 `= NH_4OH` solution at pH equal to 9.26 (q) `[OH^-]`
(C) 0.1 M `CH_3COOH` solution= 1.0 M HCOOH solution (r) α (degree of dissociation of weak electrolytes)
(D) 0.1 M of a weak acid `HA_1(ka = 10^-5 )` solution < 0.01 M of a weak acid `HA_2(k_a = 10^-6)` solution(S) pH
C

(A- p, q, r, s) ; (8- p, r) ; (C- r) ; (D- p, q, s)

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

Find instant solution to any question from our database of 1.5 Lakh + Questions

 


Access free resources including

  • 100% free video lectures with detailed notes and examples
  • Previous Year Papers
  • Mock Tests
  • Practices question categorized in topics and 4 levels with detailed solutions
  • Syllabus & Pattern Analysis

Engineering


Medical


Banking


DEFENCE


SSC


RRB


CBSE-NCERT


OLYMPIAD