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Q 2672445336.     (a) Explain why electrolysis of aqueous solution of NaCl gives `H_2` at cathode and `Cl_2` at anode. Write overall reaction.
`(( E_(Na^+//Na) = -2.71 V ; E_(H_2Cl//H_2) = -0.83 V), (E_(Cl_2//2Cl^-) = + 1.36V; E_(H^+ + O_2//H_2O) = 1.23 V))`
(b) Calculate the emf of the cell `Zn|Zn^(2+) (0.1 M) || Cd^(2+) (0.01 M)|Cd` at 298 K, [Given `E_(Zn^(2+)//Zn)^0 = - 0.76 V` and `E_(Cd^(2+)//Cd) = - 0.40 V` ]
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)