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Q 2642667533.    

Assertion : For the reaction : `Ni^(++) + 2 e^(-) -> Ni` `Fe^(++) + 2 e^(-) -> Fe` `=> E_(Fe^(++)|Fe)^0 < E_(Ni^(++)|Ni)` and `E_(red)^0 > 0` `=>` So, Fe electrode is cathode and Ni electrode is anode

Reason : Because `DeltaG^o < 0` and `E_(Cell)^0 > 0`, so cell is possible.

A Both A and R individually true and R is the correct explanation of A
B Both A and R are individually true but R is not the correct explanation of A
C A is true but R is false
D A is false but R is true

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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