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Q 2650556414.     Following cell has EMF 0.7995 V.
`Pt | H_2 (1 atm) | HNO_3(1M) || AgNO_3 (1M) |Ag`
If we add enough KCI to the Ag cell so that the final `Cl^-` is 1M Now the measured emf of the cell is 0.222 V.
The `K_(sp)` of AgCI would be
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)