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Q 2535534462.     The emf of the following cell is 0.2905 V at 298 K.
`Zn|Zn^(2+) (a= 0.1 M) | |Fe^(2+) (a= 0.01 M) | Fe`
The value of equilibrium constant for the cell reaction is
JEE 2004 Prelims
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