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Q 3079580416.     The following concentrations were obtained for the formation of `NH_3` from `N_2` and `H_2` at equilibrium at `500K`. `[N_2] = 1.5 × 10^(–2)M. [H_2] = 3.0 ×10^(–2) M` and `[NH_3] = 1.2 ×10^(–2)M`. Calculate equilibrium constant.
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