`0.56 g KOH` is added to `100` mL of `0.1 N H_2SO_4`. The resulting solution will be

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Q 2372478336.     `0.56 g KOH` is added to `100` mL of `0.1 N
H_2SO_4`. The resulting solution will be
A

neutral

B

acidic

C

basic

D

none of these

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Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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