Equation of the sphere with centre in the positive octant which passes through the circle `x^2 + y^2 = 4, z = 0` and

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Q 2127180081.     Equation of the sphere with centre in the positive octant

which passes through the circle `x^2 + y^2 = 4, z = 0` and is

cut by the plane `x + 2y + 2z = 0` in a circle of radius `3` is `........................`
A

`x^2 + y^2 + z^2 - 6z - 4 = 0`

B

`x^2 + y^2 + z^2 + 6z - 4 = 0`

C

`x^2 - y^2 + z^2 - 6z - 4 = 0`

D

`x^2 + y^2 + z^2 - 6z + 4 = 0`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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