The equation of the plane which passes through the x-axis and perpendicular to the line (x-1)/(cos theta) = (y+2)/

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Q 2176712676.     The equation of the plane which passes through the x-axis

and perpendicular to the line (x-1)/(cos theta) = (y+2)/(sin theta) = (z-3)/0 is
A

x tan theta + y sec theta = 0

B

x sec theta + y tan theta = 0

C

x cos theta + y sin theta = 0

D

x sin theta - y cos theta = 0`

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(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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