The foot of the perpendicular from `P(1, 0, 2)` to the line `(x+1)/3 = (y-2)/-2 = (z+1)/-1` is the point

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Q 2126334271.     The foot of the perpendicular from `P(1, 0, 2)` to the line

`(x+1)/3 = (y-2)/-2 = (z+1)/-1` is the point
A

` (1, 2,- 3)`

B

`(1/2 ,1 , -3/2)`

C

`(2, 4, - 6)`

D

`(2, 3, 6)`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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