The plane `4x + 7 y + 4z + 81 = 0` is rotated through a right angle about its line of intersection with the plane

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Q 2116223179.     The plane `4x + 7 y + 4z + 81 = 0` is rotated through a right

angle about its line of intersection with the plane

`5x + 3y + 10z = 25`. The equation of the plane in its new

position is `x - 4y + 6z = k`, where `k` is
A

`106`

B

`-89`

C

`73`

D

`37`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

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