A 0.001 molal solution of `Pt(NH_3)_4Cl_4` in water had a freezing point depression of 0.0054°C. If `K_f` for water is

Ask a Question


Question Asked by a Student from EXXAMM.com Team


Q 2186612577.     A 0.001 molal solution of `Pt(NH_3)_4Cl_4` in water had a freezing point depression of 0.0054°C. If `K_f` for water is 1.80, the correct formula for the above compound assuming its complete dissociation is
A

`[Pt(NH_3)_4Cl_3]Cl`

B

`[Pt(NH_3)_4Cl_2]Cl_2`

C

`[Pt(NH_3)_4Cl]C_3l`

D

`[Pt(NH_3)_4Cl_4]`

HINT


Solution
(Provided By a Student and Checked/Corrected by EXXAMM.com Team)

Find instant solution to any question from our database of 1.5 Lakh + Questions

 


Access free resources including

  • 100% free video lectures with detailed notes and examples
  • Previous Year Papers
  • Mock Tests
  • Practices question categorized in topics and 4 levels with detailed solutions
  • Syllabus & Pattern Analysis

Engineering


Medical


Banking


DEFENCE


SSC


RRB


CBSE-NCERT


OLYMPIAD