Chemistry Must Do Problems of Chemical Bonding for NDA

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Must Do Problems of Chemical Bonding for NDA

Chemical Bonding and Its Electronic Theory

Q 1305434368

Which of the following compounds does not obey the octet rule?

(A)

`PF_5`

(B)

`SF_6`

(C)

`H_2SO_4`

(D)

All of the above

Solution:

All the three compounds does not contain `8` electrons in the valence shell.

Correct Answer is `=>` (D) All of the above

Q 2817367280

The formation of chemical bond is accompanied by

(A)

increase in energy

(B)

decrease in energy

(C)

neither decrease nor increase in energy

(D)

the repulsive forces overcoming the attractive forces

Solution:

All the three compounds does not contain `8` electrons in the valence shell.

Correct Answer is `=>` (B) decrease in energy

Q 1324067851

Which of the following does not obey the octet rule?

(A)

` BCl_3`

(B)

`BeH_2`

(C)

`LiCH_3`

(D)

All of the above

Solution:

All the three compounds does not contain `8` electrons in the valence shell.

Correct Answer is `=>` (D) All of the above

Q 2817367289

Carbon suboxide (`C_3O_2`) has recently been shown as a component of the atmosphere of Venus. which of the following formulation represents the correct ground state Lewis structure for `C_3O_2`?

(A)

`:O : C : C : : O :`

(B)

`:O : C : : C : O :`

(C)

`: O :: C :: C :: C ::O :`

(D)

`: O : : C C :: O :`

Solution:

All the three compounds does not contain `8` electrons in the valence shell.

Correct Answer is `=>` (C) `: O :: C :: C :: C ::O :`

Q 1385223167

Lewis Octet rule was failed to explain the following structure of molecule

(A)

`HF`

(B)

`H_2O`

(C)

`BF_3`

(D)

`NH_3`

Solution:

Lewis Octet rule could not explain the structure of `BF_3` molecule.

Correct Answer is `=>` (C) `BF_3`

Q 1745601563

If the electronic configuration of an element is `1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4s^2`,
the four electrons involved in chemical bond formation will be
NCERT Exemplar

(A)

`3p^6`

(B)

`3p^6, 4s^2`

(C)

`3p^6 , 3d^2`

(D)

`3d^2, 4s^2`

Solution:

The given electronic configuration shows that an element is vanadium (Z=22). It
belongs to d-block of the periodic table. In transition elements i.e., d-block elements,
electrons of ns and (n- 1) d subs hell take part in bond formation.

Correct Answer is `=>` (D) `3d^2, 4s^2`

Q 1705301268

Polarity in a molecule and hence the dipole moment depends primarily on
electro negativity of the constituent atoms and shape of a molecule. Which
of the following has the highest dipole moment?
NCERT Exemplar

(A)

`CO_2`

(B)

`HI`

(C)

`H_2O`

(D)

`SO_2`

Solution:

`CO_2` being symmetrical has zero dipole moment

Among `HI`, `SO_2` and `H_2O` dipole moment is highest for `H_2O` as in it the central atom
contains 2 lone pairs

Correct Answer is `=>` (C) `H_2O`

Q 1374123956

Which of the following obeys the octet rule?

(A)

`C Cl_4`

(B)

`O_2`

(C)

`NF_3`

(D)

All of the above

Solution:

As per octet rule, all the atoms contain `8` electrons in the valence shell.

Correct Answer is `=>` (D) All of the above

Valency

Q 1354445354

An atom of one element `A` has four electrons in its outermost shell, and that of `B` has six electrons in the outermost shell. The formula of the compound formed by these two will be

(A)

`A_2B`

(B)

`AB_2`

(C)

`A_2B_3`

(D)

`A_3B_2`

Solution:

`B` completes its octet by sharing `2` electrons. `A` completes its octet by `4` electrons.

So, the compound formed should be `AB_2` ,eg : `CO_2`

Correct Answer is `=>` (B) `AB_2`

Q 2877167086

An element has the electronic configuration `1s^2 , 2s^2 2p^6 , 3 s^2 3 p^2`. The number of valence electrons
will be

(A)

`2`

(B)

`3`

(C)

`4`

(D)

`5`

Solution:

`B` completes its octet by sharing `2` electrons. `A` completes its octet by `4` electrons.

So, the compound formed should be `AB_2` ,eg : `CO_2`

Correct Answer is `=>` (C) `4`

Q 2877267186

The formula of a metallic chloride is `MCl_2`, the formula of its bicarbonate is

(A)

`MCO_3`

(B)

`MHCO_3`

(C)

`M(HCO_3)_2`

(D)

`M(CO_3)_2`

Solution:

`B` completes its octet by sharing `2` electrons. `A` completes its octet by `4` electrons.

So, the compound formed should be `AB_2` ,eg : `CO_2`

Correct Answer is `=>` (C) `M(HCO_3)_2`

Q 1745601563

If the electronic configuration of an element is `1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4s^2`,
the four electrons involved in chemical bond formation will be
NCERT Exemplar

(A)

`3p^6`

(B)

`3p^6, 4s^2`

(C)

`3p^6 , 3d^2`

(D)

`3d^2, 4s^2`

Correct Answer is `=>` (D) `3d^2, 4s^2`

Q 2817267189

Two elements gallium and oxygen combine to form a compound `Ga_2O_3`. Which among the following is the valency of gallium?

(A)

`1`

(B)

`2`

(C)

`3`

(D)

`4`

Correct Answer is `=>` (C) `3`

Q 1202391238

Two elements X and Y have following electronic configuration -

`X` `1s^2 , 2s^2 , 2p^6 ; 3s^2 , 3p^6 , 4s^2`

`Y` `1s^2 , 2s^2 , 2p^6 ; 3s^2 , 3p^5`

The expected compound formed by combination of `X` and `Y` will be expressed as-

(A)

`XY_2`

(B)

`X_5Y_2`

(C)

`X_2Y_5`

(D)

`XY_5`

Solution:

Valency of element `X` is `2` (`2` electrons in the outermost shell) while that of element `Y` is `1` (`1` electron required in the outermost shell to complete octet) so the formula of the compound between `X` and `Y` is `XY_2`

Correct Answer is `=>` (A) `XY_2`

Q 2847267183

Outermost shells of two elements X and Y have two and six electrons respectively. If they combine the expected formula of the compound will be

(A)

`XY`

(B)

`X_2 Y`

(C)

`X_2 Y_3`

(D)

`XY_3`

Correct Answer is `=>` (A) `XY`

Q 2817767680

Match List I with List II and select the correct answer from the codes given below the lists.

Column I		Column II
(A)	K	(P)	two
(B)	Zn	(Q)	one
(C)	Al	(R)	four
(D)	C	(S)	three

(A)

2 1 4 3

(B)

2 3 1 4

(C)

3 1 4 2

(D)

3 4 1 2

Correct Answer is `=>` (A) 2 1 4 3

Q 1252391234

An atom of element `A` has three electrons in its outer shell and `B` has six electrons in its outermost shell. The formula of the compound formed between these will be-

(A)

`A_6 B_6`

(B)

`A_2 B_3`

(C)

`A_3 B_2`

(D)

`A_2B`

Solution:

In this case the valence electron in the atom `A` is three and hence its valency is generally `3`. In the atom `B` the number of valence electron is six. Hence its valency is usually `2`. Hence the formula of the molecule formed from `A` and `B` could be `A_2B_3`. An example of two such elements are `Al` and `O` and the formula of Aluminium oxide `Al_2O_3`.

Correct Answer is `=>` (B) `A_2 B_3`

Ionic, Covalent and Co-ordinate Bond

Q 1188491307

The bond between two identical non-metal atoms has a pair of electrons
JEE 1986

(A)

with identical spins

(B)

unequally shared between the two

(C)

transferred fully from one atom to another

(D)

equally shared between them

Solution:

Bonds between identical, non-metal, is purely covalent due to same electronegatives of the bonded atoms. Hence, the bonded atoms have equal holds on the shared pair of electrons.

The correct answer is: equally shared between them

Correct Answer is `=>` (D) equally shared between them

Q 1504867758

Which of the following does not contain any coordinate bond?
BITSAT 2011

(A)

` H _{ 3 } O ^{ + }`

(B)

`BF _{ 4 }^{ - }`

(C)

` HF _{ 2 }^{ - }`

(D)

`NH _{ 4 }^{ + }`

Solution:

Among the given , only `HF_2^(-)` has `H`- bonding `[F-H....F]^-`. Rest all the molecules have coordinate bonds.

Correct Answer is `=>` (C) ` HF _{ 2 }^{ - }`

Q 2827367281

An electrovalent compound does not show isomerism due to

(A)

high melting point

(B)

presence of ions

(C)

strong electrostatic force between lens

(D)

non-directional nature of electrovalent bond

Solution:

Among the given , only `HF_2^(-)` has `H`- bonding `[F-H....F]^-`. Rest all the molecules have coordinate bonds.

Correct Answer is `=>` (D) non-directional nature of electrovalent bond

Q 2837367282

Elements whose electronegativities are `1.2` and `3.0`, bond formed between them would be

(A)

ionic

(B)

covalent

(C)

coordinate

(D)

metallic

Solution:

Among the given , only `HF_2^(-)` has `H`- bonding `[F-H....F]^-`. Rest all the molecules have coordinate bonds.

Correct Answer is `=>` (A) ionic

Q 1188291107

The compound which contains both ionic and covalent bonds is
JEE 1979

(A)

`CH_4`

(B)

`KCN`

(C)

`H_2`

(D)

`KCl`

Solution:

In `KCN,` the bonding between potassium ion and cyanide ion is ionic while carbon and nitrogen are covalently bonded in cyanide ion as:

The correct answer is: `KCN`

Correct Answer is `=>` (B) `KCN`

Q 2867367285

Which one of the following has high melting and boiling points?

(A)

`C Cl_4`

(B)

`AlCl_3`

(C)

`CaCl_2`

(D)

`NCl_3`

Solution:

In `KCN,` the bonding between potassium ion and cyanide ion is ionic while carbon and nitrogen are covalently bonded in cyanide ion as:

The correct answer is: `KCN`

Correct Answer is `=>` (C) `CaCl_2`

Q 2877367286

Which one of the following has a giant covalent structure?

(A)

`PbO_2`

(B)

`SiO_2`

(C)

`NaCl_2`

(D)

`AlCl_3`

Solution:

In `KCN,` the bonding between potassium ion and cyanide ion is ionic while carbon and nitrogen are covalently bonded in cyanide ion as:

The correct answer is: `KCN`

Correct Answer is `=>` (B) `SiO_2`

Q 1442712633

Th type of bond formed by `CO` with haemoglobin in blood is

(A)

Covalent

(B)

Dative

(C)

Ionicbond

(D)

Vanderwallsforces

Solution:

The type of bond formed by `CO` with haemoglobin in blood is dative.

Correct Answer is `=>` (B) Dative

Q 2847467383

Which contain both polar and non-polar bonds?

(A)

`NH_4Cl`

(B)

`HCN`

(C)

`H_2O_2`

(D)

`CH_4`

Solution:

The type of bond formed by `CO` with haemoglobin in blood is dative.

Correct Answer is `=>` (C) `H_2O_2`

Q 2857467384

Which of the following having electrovalent, covalent and coordinate covalent bond?

(A)

`BF_3`

(B)

`CuCl_2`

(C)

`CuSO_4 · 5H_2O`

(D)

`FeCl_3 · H_2O`

Solution:

The type of bond formed by `CO` with haemoglobin in blood is dative.

Correct Answer is `=>` (C) `CuSO_4 · 5H_2O`

Q 1305534468

Which of the following species contain covalent coordinate bonds? `(i) AlCl_3` `(ii) CO ` `(iii) [Fe(CN)_6]^{4-}` `(iv) NO_3^{-}`

(A)

`(i),(ii)` and `(iii) `

(B)

`(i),(ii)` and `(iv)`

(C)

`(ii),(iii) ` and `(iv)`

(D)

`(i),(iii) ` and `(iv)`

Solution:

The type of bond formed by `CO` with haemoglobin in blood is dative.

Correct Answer is `=>` (C) `(ii),(iii) ` and `(iv)`

Q 2887467387

Which one of the following has odd electron bond ?

(A)

`PCl_3`

(B)

`SF_4`

(C)

`NO`

(D)

`POCl_3`

Solution:

The type of bond formed by `CO` with haemoglobin in blood is dative.

Correct Answer is `=>` (C) `NO`

Q 2877667586

Match List I with List II and select the correct answer from the codes given below the lists:

Column I		Column II
(A)	Ionic cornpound	(P)	`NH_4Cl`
(B)	Polar covalent	(Q)	`O_2`
(C)	Non-polor covalent molecule	(R)	`HCl`
(D)	Dative bond	(S)	`KCl`

(A)

4 3 2 1

(B)

1 3 2 4

(C)

4 1 2 3

(D)

1 2 4 3

Solution:

The type of bond formed by `CO` with haemoglobin in blood is dative.

Correct Answer is `=>` (A) 4 3 2 1

Q 2837567482

Consider the properties related to co-ordinate or dative linkage compounds.
I. They are rigid and directional.
II. They exhibit isomerism.
III. They contain high dielectric constants.
IV. They are poor conductors of electricity in solid as well as in fused state.

(A)

I, II and III

(B)

II, III and IV

(C)

I, III and IV

(D)

All of these

Solution:

The type of bond formed by `CO` with haemoglobin in blood is dative.

Correct Answer is `=>` (D) All of these

Q 2817467389

Consider the following statements.
I. `NaCl` is ionic solid.
II. Benzene is covalent compound.
III Carbon has tetravalency.

(A)

I and II

(B)

II and III

(C)

I and III

(D)

All of these

Solution:

The type of bond formed by `CO` with haemoglobin in blood is dative.

Correct Answer is `=>` (D) All of these

Q 2807567488

Assertion : Purely covalent compounds cannot conduct electricity in their aqueous solution or in molten state.

Reason : Purely covalent compounds have lower melting and boiling points.

(A)

Both A and R individually true and R is the correct explanation of A

(B)

Both A and R are individually true but R is not the correct explanation of A

(C)

A is true but R is false

(D)

A is false but R is true

Solution:

The type of bond formed by `CO` with haemoglobin in blood is dative.

Correct Answer is `=>` (B)

Q 1324078851

`NH_3` and `BF_3` form an adduct readily because they form

(A)

an ionic bond

(B)

a hydrogen bond

(C)

a covalent bond

(D)

a coordinate bond

Solution:

This is co-ordinate bond between `N` and `B`.

Correct Answer is `=>` (D) a coordinate bond

Q 2847367283

Ionie bond formation is

(A)

exothermic

(B)

endothermic

(C)

Both (a) and (b)

(D)

None of these

Solution:

This is co-ordinate bond between `N` and `B`.

Correct Answer is `=>` (A) exothermic

Q 2857367284

Many ionic crystals dissolve in water because

(A)

water is an amphiprotic solvent

(B)

water is high boiling liquid

(C)

the process is accompained by positive heat of solution

(D)

water decreases the interionic attraction in the crystal lattice due to solvation

Solution:

This is co-ordinate bond between `N` and `B`.

Correct Answer is `=>` (D) water decreases the interionic attraction in the crystal lattice due to solvation

Q 1186356277

Which of the following contains both electrovalent and covalent bonds ?

(A)

`CH_4`

(B)

`H_2O_2`

(C)

`NH_4Cl`

(D)

None of these

Solution:

As shown in fiqure, `NH_4Cl` contains both electrovalent and covalent bonds.

Correct Answer is `=>` (C) `NH_4Cl`

Q 2887367287

Which one of the following is a covalent molecule ?

(A)

`Al_2Cl_6`

(B)

`Al_2O_3`

(C)

`AlF_3`

(D)

All of these

Solution:

As shown in fiqure, `NH_4Cl` contains both electrovalent and covalent bonds.

Correct Answer is `=>` (A) `Al_2Cl_6`

Q 2837467382

Both ionic and covalent bond present in

(A)

`CH_4`

(B)

`NaCl`

(C)

`SO_2`

(D)

`KOH`

Solution:

As shown in fiqure, `NH_4Cl` contains both electrovalent and covalent bonds.

Correct Answer is `=>` (D) `KOH`

Q 1314134950

The type of bonds present in `CuSO_4. 5H_2O` are only

(A)

covelent and co-ordinate

(B)

electrovalent and co-ordinate

(C)

electrovalent and covalent

(D)

electrovalent , covalent and co-ordinate

Solution:

`Cu^{2+}` and `SO_4^{2-}` from ionic bond.

`SO_4^{2-}` has covalent bonds and `H_2O` shows co-ordinate bonds.

Correct Answer is `=>` (D) electrovalent , covalent and co-ordinate

Q 2867467385

Type of bonds present in `K_4 [Fe(CN)_6]` molecule is

(A)

covalent and electrovalent bonds

(B)

covalent and coordinate covalent bonds

(C)

electrovalent, covalent and dative bonds

(D)

electrovalent bond and dative bonds

Solution:

`Cu^{2+}` and `SO_4^{2-}` from ionic bond.

`SO_4^{2-}` has covalent bonds and `H_2O` shows co-ordinate bonds.

Correct Answer is `=>` (C) electrovalent, covalent and dative bonds

Q 2807467388

Which of the following is soluble in water ?

(A)

`CS_2`

(B)

`C_2H_5OH`

(C)

`C Cl_4`

(D)

`CHCl_3`

Solution:

`Cu^{2+}` and `SO_4^{2-}` from ionic bond.

`SO_4^{2-}` has covalent bonds and `H_2O` shows co-ordinate bonds.

Correct Answer is `=>` (B) `C_2H_5OH`

Q 2817667580

Assertion : Fluorine exhibits the same oxidation state in all its compounds.

Reason : Fluorine atom has no d-orbital in its valence shell.

(A)

Both A and R individually true and R is the correct explanation of A

(B)

Both A and R are individually true but R is not the correct explanation of A

(C)

A is true but R is false

(D)

A is false but R is true

Solution:

`Cu^{2+}` and `SO_4^{2-}` from ionic bond.

`SO_4^{2-}` has covalent bonds and `H_2O` shows co-ordinate bonds.

Correct Answer is `=>` (A)

Q 2817567480

Which of the following statements are true?
I. Water is liquid at room temperature due to hydrogen bonding.
II. Covalent bond is directional.
III . Co - ordinate or dative bond containing compounds have high values of dielectric constant.

(A)

I and II

(B)

II and III

(C)

I and III

(D)

All of these

Solution:

`Cu^{2+}` and `SO_4^{2-}` from ionic bond.

`SO_4^{2-}` has covalent bonds and `H_2O` shows co-ordinate bonds.

Correct Answer is `=>` (D) All of these

Q 2867567485

Assertion : Water `(H_2O)` is more polar than hydrogen sulphide `(B_2S)`.

Reason : Oxygen is more electronegative than sulphur.

(A)

Both A and R individually true and R is the correct explanation of A

(B)

Both A and R are individually true but R is not the correct explanation of A

(C)

A is true but R is false

(D)

A is false but R is true

Solution:

`Cu^{2+}` and `SO_4^{2-}` from ionic bond.

`SO_4^{2-}` has covalent bonds and `H_2O` shows co-ordinate bonds.

Correct Answer is `=>` (A)

Diploe Moment and Hydrogen Bond

Q 1705301268

(A)

`CO_2`

(B)

`HI`

(C)

`H_2O`

(D)

`SO_2`

Solution:

`CO_2` being symmetrical has zero dipole moment

Among `HI`, `SO_2` and `H_2O` dipole moment is highest for `H_2O` as in it the central atom
contains 2 lone pairs

Correct Answer is `=>` (C) `H_2O`

Q 2807367288

Which one of the following is correct?

(A)

Water is a non-polar molecule in normal conditons

(B)

Water is a polar molecule in normal conditions

(C)

Water exist in tile form of `H^(+) OH^-` in normal conditions

(D)

All of the above are correct

Solution:

`CO_2` being symmetrical has zero dipole moment

Among `HI`, `SO_2` and `H_2O` dipole moment is highest for `H_2O` as in it the central atom
contains 2 lone pairs

Correct Answer is `=>` (B) Water is a polar molecule in normal conditions

Q 2817467380

Hydrogen fluoride is a liquid unlike other hydrogen halides because

(A)

`HF` molecule associate due to hydrogen bonding

(B)

`F_2`, is highly reactive

(C)

`HF` is the weakest acids of all hydrogen halides

(D)

fluorine atoms is the smallest of all halides

Solution:

`CO_2` being symmetrical has zero dipole moment

Among `HI`, `SO_2` and `H_2O` dipole moment is highest for `H_2O` as in it the central atom
contains 2 lone pairs

Correct Answer is `=>` (A) `HF` molecule associate due to hydrogen bonding

Q 1315334269