5%
9%
10%
15%
`1`
`2`
`3`
`4`
`34. 66 g mol^(-1)`
`45.01 g mol^(- 1)`
`52.00 g mol^(-1)`
`104.00 g mol^(- 1)`
5
7
9
11
One can add to a vessel only `2` mol of `CO` for each mol of `O_2` is added
No matter how much of these two reagents are added to a vessel, `1` mol of `O_2` is consumed
When they react, `CO` reacts with `O_2` in a `2 : 1` mol ratio
When `2` mol of `CO` and `1` mol of `O_2` are placed in a vessel, they will react to give `1` mol of `CO_2`
`42.15 g`
`84.30 g`
`126.00 g`
`154.00 g`
all the `O_2 (g)` is consumed
`4.0` mol `NO (g)` is produced
`1.5` mol `H_2O (l)` is produced
all the `NH_ 3 (g)` is consumed
`NaOH + Al + H_2O -> 2H_2 + NaAlO_2`
`2NaOH + 2Al + 2H_2O -> 3H_2 + 2NaAlO_2`
`2NaOH + 2Al + 3H_2O -> 4H_2 + 2NaAlO_2`
`2NaOH + 2Al + H_2O -> H_2 + 2NaAlO_2`
98
60
100
49
The atomic weight of an element is the sum total of the number of protons and neutrons present in the atom of the element
Unlike mass number, the atomic weight of an element can be a fraction
The atomic weight of an element is a whole number
The atomic weight of all the atoms in an element is the same
(This question may have multiple correct answers)
`100`
`200`
`300`
`400`
`4.84 xx 10^17`
`4.184 xx 10^16`
`6.023 xx 10^19`
`6.023 xx 10^23`
`H_2SO_4`
`KMnO_4`
`H_2C_2O_4`
`NaOH`
`6.023xx10^(-23)`
`1.66 xx 10^(-24)`
`6.62 xx 10^(-24)`
none of these
Zinc
Silver
Calcium
Iron
`text()^1H_1`
`text()^12 C_6`
`text()^16 C_8`
`text()^35 C_17`